Question

the ammeter reading in the circuit below is​

Answer 1

Answer:

Hey there

Total current,

I = 11 A

Net resistance,

1/R = 1/1 + 1/2 + 1/3

1/R = (6 + 3 + 2)/6

1/R = 11/6

R = 6/11 Ω

Now,

Potential difference,

V = IR

V = 6/11 × 11

V = 6 v

Since, in parallel connection voltage is constant,

So, at 1Ω resistor V = 6 v

Then,

Current at 1 Ω resistor,

I = V/R

I = 6/1

I = 6 A

Hence, ammeter reading is 6 A

Hope you like the answer

Please mark my answer as branliest