Question

The amount in bromoform produced when 1 mole of acetone

Answer 1

So moles molecules is needed to react with 1 mol acetone. Hence 1 mol molecule will react with 2/3 mol acetone. Thus acetone is the limiting reagent and the reaction is completed

Answer 2

Question - The amount of bromoform produced when 1.0 mol of acetone reacts completely with 1.0 mol of bromine in the presence of aqueous NaOH is

Answer - Amount of bromoform produced is 1/3 moles.

CH3-C=O-CH3 --3Br2/4NaOH--> CH3-C=OONa + CHBr3

•The chemical reaction for production of bromoform from acetone in presence of bromine and sodium hydroxide is given above.

•CH3-C=O-CH3 is the chemical formula for acetone. Br2 represents bromine, NaOH is sodium hydroxide, CHBr3 is bromoform and CH3-C=OONa is sodium acetate.

•From the equation, since 3 moles of Br2 produces 1 mole of bromoform.

•Hence, 1 mole of bromine will produce 1/3 mole of bromoform.

Thus, 1/3 mole of bromoform is produced.