Question

The amount of a certain sum at compound interest for 2 yr at 5% is Rs 4410. the sum is​

Answer 1

Answer:

4000 Rs

Step-by-step explanation:

Given:

Amount = 4410 Rs

Rate℅ = 5℅

Time Period(n) = 2 years.

To Find:

Principal =?

Formula used:

$\bf Amount = p \bigg(1+ \dfrac{r}{100}\bigg)^n$

Procedure:

$\bf Amount = p \bigg(1+ \dfrac{r}{100}\bigg)^n$

Putting the known values in:-

$\sf \implies \: \: 4410 = p \bigg(1 + \dfrac{5}{100} \bigg) ^{2}$

$\sf \implies \: \: 4410 = p \bigg( \dfrac{21}{100} \bigg) ^{2}$

$\sf \implies \: \: 4410 = p \bigg(1 + \dfrac{441}{400} \bigg)$

Principal amounts to 4000 Rs

Answer 2

Given :

• Amount = 4410 Rs.

• Time = 2 Year

• Rate = 5%

To Find :

• find the sUm

Solution :

$\sf : \implies \boxed{ \: \: \: \: \: \: \sf \: A = p { \bigg \{1 + \frac{r}{100} \bigg \}}^{2} \: }$

Substitute all values :

$\sf : \implies \: \: \: \: \: \: \: \: A = p { \bigg \{1 + \frac{r}{100} \bigg \}}^{2} \\ \\ \\ \sf : \implies \: \: \: \: \: \: \: 4410 = p {\bigg \{1 + \frac{5}{100}\bigg \}}^{2} \\ \\ \\ \sf : \implies \: \: \: \: \: \: \: \: \: 4410 = p { \bigg \{\frac{21}{20}\bigg \}}^{2} \\ \\ \\ \sf : \implies \: \: \: \: \: \: \: \: 4410 = p \times \frac{441}{400} \\ \\ \\ \sf : \implies \: \: \: \: \: \: \: \: 10 = \frac{p}{400} \\ \\ \\ \sf : \implies \: \: \: \: \: \: \: \:p = 4000$