Question

The amount of acetic acid present in 100 ml of 0.1 m solution is

Answer 1

The amount of acetic acid present in 100 ml of 0.1 m solution is 0.01 ml.

According to the question,

Concentration = 0.1⋅mol⋅L−1.

Volume = 100⋅mL.

Moles of the HOAc = 0.01 mol L−1.

Explanation of the above question is as follows:

Concentration = nV, where n is the no. of moles and v is the volume present. So n=C×V.

Thus, 0.1 L×0.1 molL−1 = 0.01∙mol.