Question

the amount of acetic acid present in 100 ml of 0.1M solution is

Answer 1

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Answer 2

Given:

Volume of solution = 100ml = 0.1 L

Molarity of the solution = 0.1M

To find:

Amount of solutes = ?

Formula to be used:

n = $Molarity\times Volme$

Calculation:

n = $Molarity\times Volme$

n = $0.1\times 0.1 = 0.01 = 2 grams$

Conclusion:

The amount of acetic acid present in 100mL of 0.1M solution is 0.01 moles or 2 grams.

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