Question

The amount of acetic acid present in 100ml of 0.1M solution is

Answer 1

✅verified answer......

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Answer 2

Answer: 0.6 g

Explanation:

100 ml of 0.1 m solution

moles/volume = molarity

moles = 0.1 x 100/1000 = 0.1 x 0.1 = 0.01

molar mass of CH3COOH = 60

So, amount = 0.6 g