Question

the amount of CaO produce by decomposition one of 1/4 fourth mole of CaCO3 will be​

Answer 1

Explanation:

Chemical reaction for decomposition of calcium carbonate is :

CaCO

3

→CaO+CO

2

Molar mass of CaCO

3

=100g/mol

Molar mass of CaO=56g/mol

Molar mass of CO

2

=44g/mol

According to law of conservation of mass:

Mass of CaCO

3

= Mass of CaO + Mass of CO

2

If we have one mole of calcium carbonate it will decompose to give one mole of calium oxide and one mole of carbon dioxide.

56 g of CaO is obtained from decomposition of 100 g of CaCO

3

.

So 1.4 g of CaO is obtained from decomposition of [(100×1.4)÷56=2.5g] of CaCO

3

.

Mass of CO

2

= (2.5−1.4) g = 1.1 g