Question

the amount of CaO produced by decomposition one (1/4) fourth mole of CaCO³will be​

Answer 1

Answer

14 gms

Explanation:

CaCO3——> CaO +CO2

by stoichiometric analysis, we see that 1 mole calcium carbonate dissociates to form one mole of calcium oxide and 1 mole of CO2 so

1/4 mol CaCO3 ——> 1/4 mol CaO

molar mass of CaO= 56 gm/mol

so wt. of CaO formed = 1/4×56 = 16 gms

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