Question

The amount of certain principal is 5324rs in 3 years,conpounded annually at rate of 10 p.c.p.a. Find the principal​

Answer 1

Answer:

Amount (A) = 6655 rupees

Rate (R) = 10 p.c.p.a.

Time (N) = 3 years.

Solution:

\large{ \: A = P × (1 + \frac{r}{100})^{3}}A=P×(1+

100

r

)

3

\large{ \: 6655 = P × (1 + \frac{10}{100})^{3}}6655=P×(1+

100

10

)

3

\large{ \: = P × ( \frac{110}{100})^{3}}=P×(

100

110

)

3

so,

\huge{ \: P = \frac{6655 \times {10}^{3} }{11 \times 11 \times 11}}P=

11×11×11

6655×10

3

\huge{ \: P = 5 \times {10}^{3}}P=5×10

3

\huge{ \: = 5000}=5000

Hence,

The principal was 5000 rupees.

.

THANKS.!! ;-)

Step-by-step explanation:

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