The amount of charge Q passed in time t through a crosssection
of a wire is Q = 5 t² + 3 t + 1.
The value of current at time t = 5 s is
(a) 9 A (b) 49 A
(c) 53 A (d) None of these
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Answer:
The answer is (c) 53 A
Explanation:
Given
Q = 5 t² + 3 t + 1
dQ/dt = 10t + 3
At t= 5
dQ/dt = 10×5 + 3 = 53
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