the amount of charge that passes through the filament of electric bulb in 3 sec is 5.3C.calculate its current
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Answer:
It's current is 1.76 A
Explanation:
Given,
Amount of charge (Q) = 5.3 C
Time ( t) = 3 sec
To find: Current
Solution:
Current is defined as rate of flow of charge.
i.e i = Q / t
here, Q = 5.3 C , t = 3 sec
Substituting the values,
i = 5.3 / 3
i = 1.76 A
Therefore, It's current is 1.76 A.
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