The amount of copper deposited by one Faraday current
will be maximum in an acidic solution of one litre of
(b) 2M Cu(NO3)2
(d) 5M Cu3(PO4)2
(e) 10M CuF2
(a) 1M CuCl2
(c) 5M CuSO4
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Answered by
3
Answer:
(d)
Explanation:
Normality = No. of gram equivalent
Vol. of sol.
Here Volume of solution for each is constant.
so we will calculate normality from molarity of each.
- 2M × 1 = 2
- 5M × 3 = 15
- 10M × 1 = 10
- 1M × 1 = 1
- 5M ×1 =5
AS YOU CAN SEE HIGHEST IS FOR D.
Therefore ans. is d.
Answered by
0
Answer:
(d) 5M Cu3(PO4)2
Explanation:
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