Question

The amount of current in faraday is required for the reduction of 1 mol of cr2o7--ions to cr3+ is

Answer 1

Answer:

Answer: 6 Faraday

Explanation:

Thus 6 moles of electrons are involved in conversion of 1 mole of   to .

1 electron carry charge=

1 mole of electrons contain=electrons

Thus  

1 mole of electrons carry charge=

6 mole of electrons carry charge=

Answer 2

Answer:

6F

Step-by-step explanation:

Oxidation state of Cr changes from +6(Cr2O72−) to +3(Cr3+).

Therefore, n-factor of Cr2O72− will be nf=2(6−3)=6.

6 moles of electrons will be required for the reduction of 1 mole of Cr2O72−.

 i.e. 6F charge will be required.

Hence, option C is correct.