The amount of electricity that can deposit 108g of silver from silver nitrate solution is
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Ag^+ +e- = Ag
1 mole of Ag = 108 g
Agrequires electricity= 3
108 g of Ag requires electricity= 3*108/108 = 3
we know 1 F= 3
1 mole of Ag = 108 g
Agrequires electricity= 3
108 g of Ag requires electricity= 3*108/108 = 3
we know 1 F= 3
Abhiraj2003:
From the equation above, you can see that one mole of Ag+ requires 1 mole of electrons to deposit 1 mole of Ag metal.
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