Question

The amount of energy released in fission of 235gm of U-235 is *
(a) 1.926 x 10^13 MeV
(b) 1.926 x 10^13 J
(c) 1.926 x 10^23 MeV
(d) 1.926 x 10^23 J​

Answer 1

Concept:

A fission reaction is the splitting up of a large molecule or an atom into two or more smaller ones.

Given:

Mass of uranium $=235 gm$

The energy released per fission of uranium is $200MeV$.

Find:

The amount of energy released in the fission of $235gm$ of uranium-235 .

Solution:

The mass of uranium $=235gm$ .

The energy released per fission $=200MeV=200\times 10^6\times 1.6\times 10^{-19}=3.2\times 10^{-11}J$.

Now, the number of atoms in $235gm$ of uranium :

$n=\frac{235\times 6.023\times 10^{23}}{235}$

$n=6.023\times 10^{23}$ atoms

The total energy released :

$=n\times 200MeV\\=6.023\times 10^{23}\times 3.2\times 10^{-11}J\\=19.26\times 10^{12}J=1.926\times 10^{13}J$

The amount of energy released in the fission of $235gm$ of U-235 is $1.926\times 10^{13}J$.

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Answer 2

Answer:

The amount of energy released in the fission of 235gm of uranium-235 = 1.926 x 10¹³ J

Explanation:

A fission reaction is the splitting up of a large molecule or an atom into two or more smaller ones.

Given

Mass of uranium = 235gm

The energy released per fission of uranium is =235 MeV

Find:

The amount of energy released in the fission of 235gm of uranium-235 .

Mass of uranium = 235gm

The energy released per fission

= 200 MeV = 200 x 10⁶ x 1.6 x 10 ⁻¹⁹  = 3.2 x 10 ⁻¹¹J

Now, the number of atoms in 235 gm of uranium :

n = 235 x 6.023 x 10²³ / 235

n = 6.023 x 10²³ atoms

The total energy released :

= n x 200 MeV

= 6.023 x 10²³ atoms  x 3.2 x 10 ⁻¹¹J

= 19.26 x 10 ¹² J

= 1.926 x 10¹³ J

The amount of energy released in the fission of 235gm of uranium-235 = 1.926 x 10¹³ J

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