Question

the amount of H2O2 present in 1 litre of H2O2 solution having volume strength 100v is

Answer 1



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The strength of H2O2 (in g/litre) in 11.2...

The strength of H2O2 (in g/litre) in 11.2 volume solution of H2O2 is?

one year ago

Answers : (1)

@rithesh 
volume strength is an outdated term referring to the volume of oxygen gas liberated from 1 volume of h2o2 solution . 
for example – if the volume strength is 20 volume , it means that 1 cm3 of h2o2 will produce from 20 cm3 of oxygen gas . 
acc to the equation 
2 moles of h2o2 = 22.4 L of oxygen at STP . 
so, by that first of all u have to calculate the MOLARITY of the solution . 
and use the formula 
moles of solute / volume of solution 
and the volume of solution is given as 11.2 
and u ned to calculate the no of moles . 
and use the formula 
mass/ molar mass , or given mass / molar mass 
and findout the no of moles , 

THE STRENGTH CAN BE CALCULATED BY THE FOLLOWING FORMULA 
11.2 * MOLARITY OF THE SOLUTION . 
from the prev formula , u find molaritty and apply it here , u will get the strength 
HOPE IT CLEARS YOUR DOUBT 

IF U NOT ABLE TO FIND THE ANSWER , THEN LET ME KNOW 
GOOD LUCK ..

thanks

Answer 2

29.92 grams is the amount of H₂O₂ that is present in 1L of H₂O₂ with a volume strength of 100 vol

• 100 vol  H₂O₂ means 1L  H₂O₂ has 100L O₂
• We know, 2H₂O₂ → 2H₂O + O₂
• We know that 1 mole is equal to 22.4L
• Moles of O₂ = 100 ÷ 22.4 = 0.44 moles O₂
• According to the reaction, for 1 mole O₂ consumed = 2 moles H₂O₂ are consumed
• So, for consumption of 0.44 mole of oxygen, 0.88 moles of hydrogen peroxide will be consumed.
• We know that the molecular mass of hydrogen peroxide is 34 thus, 0.88 × 34 = 29.92 grams of hydrogen peroxide is consumed.
• Thus, in 1L or 1000mL, 29.92 grams of H₂O₂ will be present.