The amount of H₂SO4 (in gram) present
in 250 ml of 1 mole solution
is ?
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Explanation:
ANSWER
No of moles (n) = 1000Molarity×VmL
Given:
M=0.5M
VmL=250mL
Therefore, n=10000.5×250=1000125=0.125mol
Molar mass of NaOH = 40g
Mass of NaOH = 0.125×40=5g
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