Question

The amount of HCl formed when 8 g of hydrogen
gas (H2) reacts with 142 g of chlorine gas (C12)
is (Atomic mass of Cl = 35.5 u)
H2 + Cl2 → 2 HCI​

Answer 1

Answer:

Required Answer :-

We may solve by

Moles of Hydrogen or H₂ =

Moles = Total Mass/Molar Mass

Moles = 8/2

Moles = 4/1

Moles = 4

Moles of CI₂ =

Moles = Total Mass/Molar Mass

Moles = 142/71

Moles = 2/1

Moles = 2

We have asked to find amount of HCI

142/71 × 73

2/1 × 73

2 × 73/1

146 g

$\begin{gathered}\\\end{gathered}$

Answer 2

Answer:

hope it's helpful to you