Question

The amount of HCl formed when 8 g of hydrogen
gas (H2) reacts with 142 g of chlorine gas (C12)
is (Atomic mass of Cl = 35.5 u)
H2 + Cl2 → 2 HCI​

Answer 1

Answer:

146g of Hcl is formed

Step-by-step explanation:

The solution is in the picture

Answer 2

Answer :-

146 grams of HCl is formed.

Explanation :-

The balanced chemical equation for the reaction is :-

H₂ + Cl₂ → 2HCl

Moles of H₂ :-

= Given Mass/Molar mass

= 8/2

= 4 moles

Moles of Cl₂ :-

= Given Mass/Molar mass

= 142/71

= 2 moles

________________________________

We have less moles of Cl₂ than H₂.

Thus, Cl₂ is the limiting reagent and will control the amount of product.

Now, according to the balanced chemical equation :-

∵ 71g of Cl₂ → 73g of HCl

∴ 142 g of Cl₂ gives :-

⇒ (142 × 73/71)g of HCl

⇒ 146g of HCl