The amount of HCl formed when 8g of hydrogen gas (H_(2)) reacts with 142g of chlorine gas (Cl_(2)) is (Atomic mass of Cl=35.5u) H_(2)+Cl_(2)rarr2HCl
Answers
Explanation:
The ratio at which the compounds react with each other are displayed in a chemical reaction as the numbers in front of the compounds. For example in this reaction:
1
H
2
molecule reacts with 1
C
l
2
molecule
Forming
2
H
C
l
molecules.
In chemistry moles are used as a handy number of a certain amount of stuff. You can compare this to a dozen eggs, which is always 12. In the same way 1 mol is the number
6.022
⋅
10
23
. This number tells us how many particles there are. So in 1 mol there are
6.022
⋅
10
23
particles. This number is also referred to as the constant of Avogadro.
In the question the amount of moles for
H
2
and for
C
l
2
are given. We have to calculate how much
H
C
l
is produced with both these values. Therefore 2 calculations needs to be done.
Because moles just tells us something about the amount of particles we can use the ratio of the reaction to calculate how many
H
C
l
will be produced.
We start of with the 2 moles of hydrogen gas. We know the following now:
1 mole of
H
2
gives 2 moles of
H
C
l
Therefore
2 moles of
H
2
gives 4 moles of
H
C
l
Now this same calculation can be done for the
C
l
2
:
1 mole of
C
l
2
reacts to 2 moles of
H
C
l
, therefore
4 moles of
C
l
2
reacts to 8 moles of
H
C
l
.
Now we see we have 2 different amount of moles for
H
C
l
and the question now is which one should we use?
We must now look at which one of above reactions can occur? So for the 2 moles of
H
2
, we can calculate with the ratio that:
2 moles of
H
2
reacts with 2 moles of
C
l
2
.
We do have 2 moles of
C
l
2
available!
Let's see the other one
4 moles of
C
l
2
reacts with 4 moles of
H
2
But we do not have 4 moles of
H
2
!!
Therefore we can only make 4 moles of
H
C
l
instead of 8 moles.
This situation can be stated as following: The
C
l
2
is abundant.
I hope you are understand my solution