India Languages, asked by arjunjayan7659, 8 months ago

The amount of heat energy necessary to rise the temperature of 5kg of water from 20 degree C to 100 degree C is kcal

Answers

Answered by BLACK1817
17

Answer:

C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C. Answer is 266.858kj1 calorie = 4.18 Joules. Thus 4180 Joules of energy of heats required for a Kilogram of water through just one degree centigrade.

Answered by Anonymous
2

Answer:

Answer:

400 Kcal

Explanation:

Data : m = 5 , c = 1 kcal/kg ,

Delta T = 100 -20 = 80 Celsius

Q = m×c×delta T

= 5 ×1 × 80

= 400

Hence heat required is 400 kcal

hope this helps u

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