The amount of heat energy required to convert 1 kg
of ice at -10°C to water at 100°C is 7,77,000 J.
Calculate the specific latent heat of ice. Specific heat
capacity of ice = 2100 J kg-1 K-1, specific heat
capacity of water = 4200 J kg-1 K-1.
Ans. 3,36,000 J kg
Answers
Answered by
1
Answer:
3.36 × 10power 5 Joules is required latent heat
Similar questions