Physics, asked by neha8420, 8 months ago

The amount of heat energy required to convert 1 kg
of ice at -10°C to water at 100°C is 7,77,000 J.
Calculate the specific latent heat of ice. Specific heat
capacity of ice = 2100 J kg-1 K-1, specific heat
capacity of water = 4200 J kg-1 K-1.
Ans. 3,36,000 J kg​

Answers

Answered by mehtarishi
1

Answer:

3.36 × 10power 5 Joules is required latent heat

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