Question

The amount of heat energy required to raise the temperature of water of mass 500g from 20degrees celicius to 25 degrees Celsius

Answer 1

The answer is given below

Answer 2

Given :

• Mass of water (m) = 500 g = 0.5 kg
• InitiaI temperature (T₁) = 20° C
• FinaI temperature (T₂) = 25° C

To find :

• Amount of heat energy required

SoIution :

As we know that :

⇔ Specific heat capacity of water (s) = 4200 J/kg C

Now we know the formuIa :

$\longmapsto\underline{\boxed{ \sf s = \dfrac{Q}{m (T_2 - T_1)} }} \\\\ \longmapsto\sf 4200 = \dfrac{Q}{0.5 (25 - 20)} \\\\ \longmapsto\sf 4200 = \dfrac{Q}{0.5 \times 5} \\\\ \longmapsto\sf 4200 = \dfrac{Q}{2.5} \\\\ \longmapsto\sf Q = 4200 \times 2.5 \\\\ \longmapsto\sf Q = 10,500 J \\\\ \longmapsto\sf Q = \dfrac{10,500}{1000} \\\\ \longmapsto\underline{\boxed{\sf{ Q = 10.5 KJ }}}$

Therefore,

Amount of heat energy required = 10,500 J/ 10.5 KJ