Physics, asked by perfect2776, 4 months ago

The amount of heat given out when 10gm of steam condenses into 10gm of boiling water at 100c

Answers

Answered by prabhas24480
2

Heat required =−100C ice to 00C ice + 00C ice to 00C water + 00C water to 1000C water + 1000C water to 1000C steam

                        =10[0.487(10)+80+1(100−0)+536]

                        =7208.7cal [since specific heat of ice=0.487cal/g-K]

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