Question

the amount of heat required in converting 1 gram of ice at -10 degree Celsius into steam at hundred degree Celsius will be

Answer 1

The amount of heat required is 725 cal.

Explanation:

We are given:

• Quantity of ice = 1 g
• Temperature "T" = - 10 °C

Solution:

msΔT = 1 x 1/2 x 10 = 5 cal

• Now 1 g ice at 0 °C

mL = 1 x 80 = 80 cal

• Now 1 g water at 0 °C

msΔT = 1 x 1 x 100 = 100 cal

• Now 1 g water at 100 °C

mL = 1 x 540 = 540 cal

• Now 1 g steam 100 °C

Total heat required = 5 + 80 + 100 + 540 = 725 cal

Hence the amount of heat required is 725 cal.

Also learn more

What will the amount of heat required to convert 50 grams of ice at 0 degree Celsius to water at 0 degrees Celsius?

https://brainly.in/question/5796606