The amount of heat required in converting 1g ice at -10°C into steam at 100°C will be :-
(1) 3028 J
(2) 6056 J
(3) 721 J
(4) 616 J
Answers
We know that the amount if Heat required for one degree rise in temperature for an ice is = mC (dt)
Therefore heat required for rising the temperature of ice at -10°C to 0°C
Q=mC (dT)
=1 (0.5)(10)
= 5 cal
The heat required for the change of state of ice to water = mL (L =Latent Heat)
Therefore heat required = mL
=(1)(80)
= 80 call
The heat required to heat water from 0°C to 100°C
=mC (dt)
=(1)(1)(100)
=100 cal
For the change of state, heat required
=mL (L = 340 cal)
=(1)(540)
=540 cal
Now we have steam at 100°C
Therefore,
The heat required = 725 × 4.184
=3033.4 J
Therefore (a) is the correct answer.
Answer:
We know that the amount if Heat required for one degree rise in temperature for an ice is = mC (dt)
Therefore heat required for rising the temperature of ice at -10°C to 0°C
Q=mC (dT)
=1 (0.5)(10)
= 5 cal
The heat required for the change of state of ice to water = mL (L =Latent Heat)
Therefore heat required = mL
=(1)(80)
= 80 call
The heat required to heat water from 0°C to 100°C
=mC (dt)
=(1)(1)(100)
=100 cal
For the change of state, heat required
=mL (L = 340 cal)
=(1)(540)
=540 cal
Now we have steam at 100°C
Therefore,
The heat required = 725 × 4.184
=3033.4 J
Therefore (a) is the correct answer.
Explanation: