Question

The amount of heat required in converting 2g ice at -10°c into steam at 100°c will be:-
1)3028 j
2)6061 j
3)721 j
4)616 j
also explain it.​

Answer 1

Answer:

4)616 j

Explanation:

hope it helps you

Answer 2

As we know
S of water = 1
S of ice =1/2
Latent heat of fusion =80
Latent heat of vapourisation=540

First we converte -10C ice to 0C ice
Q’=ms(t2-t1)
=2*1/2(0-(-10))=10j
Now 0C ice to 0C water
Q’’=m(Lf)
=2*80=160j
Now 0C water to 100C water
Q’’’=ms (t2-t1)
=2*1(100-0)=200j
100C water to 100C vapour
Q’’”=m(Lv)
=2*540=1080j
Finally
Q=Q’+Q”+Q’”+Q””
=10j+160j+200j+1080j
=1480j