The amount of heat required to convert 1 gm of ice at 0 degree celcious into water at 273 k is
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1
Answer:
4.7 joules is the required amount of heat
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38
Answer:
- (1 gm)(540 cal/gm) = 540 cal.
- Summing up the entire thing you get, total heat required = 720 cal = 0.72 kcal.
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