the amount of heat required to convert 5kg of ice at 0°c to vapour at 100°c is 36×10pcal. find the value of p
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Answer:
1.5×10 7J
Explanation:
We have , L
ice
=3.34×10
5
J/kg,m=5kg
From the definition of latent heat , heat required to convert ice into water at constant temperature 0
o
C ,
Q
1
=mL
ice
or Q
1
=5×3.34×10
5
=16.7×10
5
J
Now , heat required to heat up the water at 100
o
C from 0
o
C ,
Q
2
=mc(100−0)=5×4200×100=21×10
5
J , where c=4200J/kg−
o
C
Further ,L
w
=2.24×10
6
J/kg,m=5kg
From the definition of latent heat , heat required to convert water into vapour at constant temperature 100
o
C ,
Q
3
=mL
w
or Q
3
=5×2.24×10
6
=112×10
5
J
Total heat required ,
Q=Q
1
+Q
2
+Q
3
or Q=16.7×10
5
+21×10
5
+112×10
5
=149.7×10
5
=1.5×10
7
J
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