Science, asked by khushichawak, 2 months ago


The amount of heat required to convert water of mass 10 g at 30°C to steam at 100°C​

Answers

Answered by niyatiinn
0

Answer:

Heat required to raise temperature of ice from −10 o Cto0 o C isQ 1 =ms 1

θ=10×0.5×10=50cal

Heat required to just melt ice at 0o C is Q 2=mL 1  

=10×80=800cal

Heat required to raise temperature of water from 0 oCto100 oC isQ 3=ms 2 θ=10×1×100=1000cal

Heat .required to convert water at 100 oC into steam isQ 4 =mL 2

=10×540=5400cal

Totalheat=Q 1+Q 2 +Q 3 +Q4

=7250cal

Explanation:

Answered by chpavithra
0

Answer:

Heat required to raise temperature of ice from −10 o Cto0 o C isQ 1 =ms 1

θ=10×0.5×10=50cal

Heat required to just melt ice at 0o C is Q 2=mL 1

=10×80=800cal

Heat required to raise temperature of water from 0 oCto100 oC isQ 3=ms 2 θ=10×1×100=1000cal

Heat .required to convert water at 100 oC into steam isQ 4 =mL 2

=10×540=5400cal

Totalheat=Q 1+Q 2 +Q 3 +Q4

=7250cal

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