The amount of heat required to convert water of mass 10 g at 30°C to steam at 100°C
Answers
Answer:
Heat required to raise temperature of ice from −10 o Cto0 o C isQ 1 =ms 1
θ=10×0.5×10=50cal
Heat required to just melt ice at 0o C is Q 2=mL 1
=10×80=800cal
Heat required to raise temperature of water from 0 oCto100 oC isQ 3=ms 2 θ=10×1×100=1000cal
Heat .required to convert water at 100 oC into steam isQ 4 =mL 2
=10×540=5400cal
Totalheat=Q 1+Q 2 +Q 3 +Q4
=7250cal
Explanation:
Answer:
Heat required to raise temperature of ice from −10 o Cto0 o C isQ 1 =ms 1
θ=10×0.5×10=50cal
Heat required to just melt ice at 0o C is Q 2=mL 1
=10×80=800cal
Heat required to raise temperature of water from 0 oCto100 oC isQ 3=ms 2 θ=10×1×100=1000cal
Heat .required to convert water at 100 oC into steam isQ 4 =mL 2
=10×540=5400cal
Totalheat=Q 1+Q 2 +Q 3 +Q4
=7250cal