Question

the amount of heat required to raise the temperature of 75 kg of ice at zero degree celsius to water at 10 degree Celsius is​

Answer 1

Answer:

3.15 Mega Joule

Explanation:

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Answer 2

Answer:3.15×10^6 megajoules

Explanation:

Q=ms(T2-T1)

Where m is mass

S is specific hear and delta T is change in temperature

Here m=75 kg

S=4200 (specific heat of water)

Temperature=10

Therefore

Q=mst