the amount of heat required to raise the temperature of a body from 20℃ to 60℃ is (water equivalent of body is 10 gm).
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mass of the body is equal to 10 grams
initial temperature of the body is equal to 20 degree Celsius
final temperature of the body= 60 degree Celsius
specific heat capacity of water is equal to 1 calorie per gram degree Celsius
then, heart required = mass x specific heat capacity x change in temperature
= 10 x 1 x (60 - 20)
= 10 x 40 = 400 cal
hope this would help you
initial temperature of the body is equal to 20 degree Celsius
final temperature of the body= 60 degree Celsius
specific heat capacity of water is equal to 1 calorie per gram degree Celsius
then, heart required = mass x specific heat capacity x change in temperature
= 10 x 1 x (60 - 20)
= 10 x 40 = 400 cal
hope this would help you
kamleshverma1711:
plz mark it brainpower
Answered by
1
Answer:
400 cal
Explanation:
specific heat of water in teRMS of cal is 1
so ms∆t = 10*1*(60-20)
=10*1*40
=400cal.
please mark mine as brainliest answer
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