Question

The amount of heat required to rise the
temperature of 100 gm water from 30 °C
to 80 °C is (S = 1 cal/gm K)​

Answer 1

Answer:

Explanation:

Use,

Q=Mc delta T, mass=100gm,,delta T=50°., c=1cal/gm k

So, Q=100 x 1 x 50== 5000 cal.