The amount of internal energy needed to raise the temperature of 0.25 kg of water by 0.2c is 209.3 j. How fast must a 0.25 kg baseball travel in order for its kinetic energy to equal this internal energy?
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The baseball must travel with a speed of 40.91 m/s.
- The internal energy(U) of water that is 209.3 J must be equal to the kinetic energy of the baseball.
- Kinetic energy =( m×v²)/2.
- By equating U=( m×v²)/2 , we get v=√(2×U/m)
- v=√(2×209.3/0.25)
- Calculating the above expression will lead us to our answer that the baseball must travel with a speed of 40.91 m/s.
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