Question

The amount of internal energy needed to raise the temperature of 0.25 kg of water by 0.2c is 209.3 j. How fast must a 0.25 kg baseball travel in order for its kinetic energy to equal this internal energy?

Answer 1

The baseball must travel with a speed of 40.91 m/s.

• The internal energy(U) of water that is 209.3 J must be equal to the kinetic energy of the baseball.

• Kinetic energy =( m×v²)/2.

• By equating U=( m×v²)/2 , we get v=√(2×U/m)
• v=√(2×209.3/0.25)
• Calculating the above expression will lead us to our answer that the baseball must travel with a speed of 40.91 m/s.