Question

The amount of kClo3 needed to supply sufficient for burning 112 l of co gas at N.T.P is

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Answer 1

Answer:

112 L of CO is equal to 5 moles. We need 1 mole of Oxygen for 2 moles of CO to burn. So for 112L of CO we need 2.5 moles of O2. So 3 moles of Oxygen are obtained from 2 moles of Potassium chlorate.