Chemistry, asked by shvnbabu17, 9 months ago

The amount of lime required for the removal of 50 ppm of calcium temporary hardness in terms of CaCo3 equivalent is

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Answered by smartboytt1984
0

Answer:

Milligrams per litre (mg/l): The number of milligrams of calcium carbonate equivalent hardness presents in litre of water. 1 mg/L = 1 mg of CaCO3 eq hardness in 1 litre of water. But one litre of water weights =1 kg =1000g = 1000 x 1000 mg = 106 mg = 1 ppm. 3.

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