The amount of money in the account every year, when 10000 is deposited at compound interest at 8 % per annum
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Answered by
9
Step-by-step explanation:
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prachi6243:
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Answered by
15
Step-by-step explanation:
Amount in the beginning = Rs. 10000
Interest at the end of 1st year @ 8%
=
10000× 8% = 800
Thus, amount at the end of 1st year
=
10000+ 800= 10800
Interest at the end of 2nd year @ 8%
=
10800 × 8% = 864
Thus, amount at the end of 2nd year
=
10800+ 864 = 11664
Since, each subsequent term is not obtained by adding a fixed number to the previous term; hence, it is not an AP.
hope it helps
Interest at the end of 1st year @ 8%
=
10000× 8% = 800
Thus, amount at the end of 1st year
=
10000+ 800= 10800
Interest at the end of 2nd year @ 8%
=
10800 × 8% = 864
Thus, amount at the end of 2nd year
=
10800+ 864 = 11664
Since, each subsequent term is not obtained by adding a fixed number to the previous term; hence, it is not an AP.
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