Math, asked by prachi6243, 3 months ago


The amount of money in the account every year, when 10000 is deposited at compound interest at 8 % per annum​

Answers

Answered by Anonymous
9

Step-by-step explanation:

hope it helps you I know you are

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prachi6243: thank you
Answered by Anonymous
15

Step-by-step explanation:

Amount in the beginning = Rs. 10000

Interest at the end of 1st year @ 8%

=

10000× 8% = 800

Thus, amount at the end of 1st year

=

10000+ 800= 10800

Interest at the end of 2nd year @ 8%

=

10800 × 8% = 864

Thus, amount at the end of 2nd year

=

10800+ 864 = 11664

Since, each subsequent term is not obtained by adding a fixed number to the previous term; hence, it is not an AP.

hope it helps


Anonymous: Amount in the beginning = Rs. 10000

Interest at the end of 1st year @ 8%
=
10000× 8% = 800

Thus, amount at the end of 1st year
=
10000+ 800= 10800

Interest at the end of 2nd year @ 8%
=
10800 × 8% = 864

Thus, amount at the end of 2nd year
=
10800+ 864 = 11664

Since, each subsequent term is not obtained by adding a fixed number to the previous term; hence, it is not an AP.
Anonymous: hope it helps
prachi6243: yaa thankyou
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