Math, asked by Rejoice6942, 10 months ago

The amount of money in the account every year when rupees 10000 is deposited at compound interest at ten percent annum

Answers

Answered by tanay6694
0

Answer:

\boxed{AHOYMATEYY!!!}

Rate of interest = R = 8% p.a [at C.I.]

∴ A = P [ 1 + R/100 ] ⁿ

→ 10,000 [1+8 / 100

Step-by-step explanation:

Amount deposited initially = P = rs. 10,000

Rate of interest = R = 8% p.a [at C.I.]

∴ A = P [ 1 + R/100 ] ⁿ

→ 10,000 [1+8 / 100]

= 10,000 × 108/100

= 10800

→ 10,000 [1+8 / 100]²

= 10,000 × 108/100 × 108/100

= 11664

→ 10,000[1+8/100]³

= 10,000 × 108×108×108

                100×100×100

= 12597.12

the terms 10800, 11664, 12597.12....

a₂-a₁ = 800

a₃-a₂ = 864

a₄-a₃ = 933.12

Here, a=10,000

But, a₂-a₁ ≠ a₃-a₂ ≠ a₄-a₃

∴ the given situation doesn't represent an A.P

Answered by Anonymous
0

Step-by-step explanation:

Amount deposited initially = P = rs. 10,000

Rate of interest = R = 8% p.a [at C.I.]

∴ A = P [ 1 + R/100 ] ⁿ

→ 10,000 [1+8 / 100]

= 10,000 × 108/100

= 10800

→ 10,000 [1+8 / 100]²

= 10,000 × 108/100 × 108/100

= 11664

→ 10,000[1+8/100]³

= 10,000 × 108×108×108

                100×100×100

= 12597.12

the terms 10800, 11664, 12597.12....  

a₂-a₁ = 800

a₃-a₂ = 864

a₄-a₃ = 933.12

Here, a=10,000

But, a₂-a₁ ≠ a₃-a₂ ≠ a₄-a₃

∴ the given situation doesn't represent an A.P

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