the amount of money in the account every year when rupees 10000 is deposited at the compound interest at 8% per annum find the amount for 2 years
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Amount deposited initially = P = rs. 10,000
Rate of interest = R = 8% p.a [at C.I.]
∴ A = P [ 1 + R/100 ] ⁿ
→ 10,000 [1+8 / 100]
= 10,000 × 108/100
= 10800
→ 10,000 [1+8 / 100]²
= 10,000 × 108/100 × 108/100
= 11664
→ 10,000[1+8/100]³
= 10,000 × 108×108×108
100×100×100
= 12597.12
the terms 10800, 11664, 12597.12....
a₂-a₁ = 800
a₃-a₂ = 864
a₄-a₃ = 933.12
Here, a=10,000
But, a₂-a₁ ≠ a₃-a₂ ≠ a₄-a₃
∴ the given situation doesn't represent an A.P
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