Chemistry, asked by pratikyadav01, 5 months ago

The amount of Na2C03 needed to
prepare 100 ml of 0.1 M standard
solution of sodium carbonate.​

Answers

Answered by akankshakamble6
1

Answer:

Using the concentration equation, m = CVM where m is the mass of solute, C is the concentration, V is the volume of solution and M is molar mass of the solute:

m = 0.1mol/L(0.1L)(106g/mol) = 1.06g

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