Question

the amount of Na2CO3 present in 100 ml of 0.1M Na2CO3 solution ​

Answer 1

Answer:

1.06g

Explanation:

volume of solution= 100 ml=0.1 litre

molecular mass of Na2Co3=106g

molarity of solution given=0.1M

no.of moles of Na2Co3=x

molarity=no.of moles/vol.of solution in litre

0.1=x/0.1

x=0.01 or 10 power -2

moles= weight/molecular mass of compound

10 power-2=w/106

w=1.06g

Answer 2

Answer:

I know but I have some doubt in that