Question

the amount of Na2CO3 required to react with HCl for obtaining 0.1 mole of CO2 is?

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Answer 1

Answer:

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Answer 2

Na2CO3 + HCl ----> 2NaCl + H2O + CO2

1 mole of CO2 ---->. 106 g of Na2CO3

0.1 mole of CO2 -----> x

x = 106 * 0.1

10.6 g of Na2CO3

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