Question

The amount of NaOH required to prepare 250cm3 of 0.01M solution is?

Answer 1

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To calculate this use the following equation:

M*V=moles

where M is the molarity or mol/L and V is the volume in liters. Given the amounts in the question the molarity will be 1 M, the volume will be 250 mL or 0.25 L. So, the number of moles needed will be:

1 moles/L * 0.25 L = 0.25 moles

The molecular weight of NaOH is 23+17 = 40 g/mole so the amount needed is

0.25 moles * 40 g/mole of NaOH = 10 g of NaOH