Question

the amount of NaOH required to prepare 250cm3 of 1M solution is? ​

Answer 1

$\huge{\mathfrak{HEYA\:MATE\:!!}}$

Answer...

→let the amount required be w

volume = 250cm³ = 250 ml

Molecular mass of NaOH = 40g

Molarity ,

$M \: \: = \frac{w}{M.M. \: \times \: V(L)} \\ \\ w \: = \: 1 \: \times \: 40 \: \times \frac{250}{1000} \\ \\ w \: = 40 \times \frac{1}{4} \\ \\ w \: = \: 10 \: g$

$\mathscr{\large{Hope\:helps\:}}!! \\ \\ {GRACIAS!!}$

$\huge{\red{\ddot{\smile}}}$

Answer 2

Here's your answer....

Hope it helps...

Please mark as brainliet....

Have a good day.☺