Question

The amount of oxalic acid (Eq. Wt. 63) required to prepare 500 ml of its 0.10N solutions is​

Answer 1

Answer:

Hence, mass of oxalic acid required is 3. 15 g.

Explanation:

Answer 2

Answer:

• $3.15\:gr$

Explanation:

$N = \dfrac{W}{GEW}\times \dfrac{1000}{V_{ml}}$

$W = N\times GEW\times \dfrac{V_{ml}}{1000}$

$W = 0.10\times 63\times \dfrac{500}{1000}$

$W = \dfrac{1}{10} \times 63\times \dfrac{500}{1000}$

$W = 63\times \dfrac{50}{1000}$

$W = 63\times \dfrac{1}{20}$

$W = \dfrac{63}{20}$

$W = 3.15 \:gr$