Question

The amount of oxalic acid (H2C2O4.2H2O) required to prepare 100mL of 0.2M solution is​

Answer 1

Answer:

2.52 g

Explanation:

Molecular weight of oxalic acid = 126 g/mol

Volume of Solution to be prepared = 100 mL = 0.1 L

Moles of oxalic acid , n = given weight / molecular weight

n = x / 126

Molarity = Moles / Volume

0.2 = x / (126 × 0.1)

x = 0.2 × 126 × 0.1

x = 2.52 g

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