The amount of oxygen formed when12 .26 g of KCIO3 is heated is
a)4.8g
b)48.0g
c) 44.8g
d) 4.48g
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⭕Here is your answer mate ⭕
The chemical equation for decomposition of KClO3 can be written as:
2KClO3 →2KCl+3O2
245 g of KClO3 gives 67.2 L of O2 at STP.
12.26g of KClO3 gives (96*12.6)/245=
4.8 grams.
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