Math, asked by aliarain1, 4 months ago

the amount of petrol in the fuel tank of three cars A , B, and C are in the ratio 8:10:13. if the tank with the smallest amount of petrol has 52 liters of petrol, find the difference in the amount of petrol in the other two cars

Answers

Answered by Rameshjangid
0

Answer:

      The difference in the amount of petrol in the other two cars = 19.5 liters.

Explanation:

  • Given that the amount of petrol in the fuel tank of three cars A , B, and C are in the ratio 8 :10 :13.
  • The tank with the smallest amount of petrol has 52 liters of petrol.
  • We have to find the difference in the amount of petrol in the other two cars.
  • From the given ratio, the amount of petrol in liters can be considered as 8x, 10x, 13x. Where x is the common factor.
  • From the ratio it is clear that the smallest amount of petrol is 8x.
  • Therefore, the smallest amount of petrol 52 liters = 8x

        8x = 52

    ⇒ x = \frac{52}{8} = 6.5 liters

  • Therefore, the value of x = 6.5. Now we can find the amount of petrol in the other two cars.

For first car amount of petrol = 10x = 10 × 6.5 = 65 liters

For second car amount of petrol = 13x = 13 × 6.5 = 84.5 liters

  • Now we can find the difference in the amount of petrol in the two cars = 84.5 - 65 = 19.5 liters.
  • Hence, the difference in the amount of petrol in the other two cars = 19.5 liters.

To know more, go through the links;

https://brainly.in/question/6481437

https://brainly.in/question/17587334

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