the amount of petrol in the fuel tank of three cars A , B, and C are in the ratio 8:10:13. if the tank with the smallest amount of petrol has 52 liters of petrol, find the difference in the amount of petrol in the other two cars
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Answer:
The difference in the amount of petrol in the other two cars = 19.5 liters.
Explanation:
- Given that the amount of petrol in the fuel tank of three cars A , B, and C are in the ratio 8 :10 :13.
- The tank with the smallest amount of petrol has 52 liters of petrol.
- We have to find the difference in the amount of petrol in the other two cars.
- From the given ratio, the amount of petrol in liters can be considered as 8x, 10x, 13x. Where x is the common factor.
- From the ratio it is clear that the smallest amount of petrol is 8x.
- Therefore, the smallest amount of petrol 52 liters = 8x
8x = 52
⇒ x = = 6.5 liters
- Therefore, the value of x = 6.5. Now we can find the amount of petrol in the other two cars.
For first car amount of petrol = 10x = 10 × 6.5 = 65 liters
For second car amount of petrol = 13x = 13 × 6.5 = 84.5 liters
- Now we can find the difference in the amount of petrol in the two cars = 84.5 - 65 = 19.5 liters.
- Hence, the difference in the amount of petrol in the other two cars = 19.5 liters.
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