The amount of quick lime that can be produced by heating 100gof 90%pure le stone. What is the answer?
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Explanation:
Heating of limestone shown by:
CaCo3-->CaO+Co2
From the balancing chemical equation:
100 g of CaCo3 decomposes to give 56 g of CaO
Thus when purityis 100%,the mass of CaO obtained by heating 100 g of lime stone is=
56 g
When purity is 90% the mass of CaCo3 is 90/100×100=90 g
100 g of CaCo3 gives=56 g of CaO
90 g of CaCo3 gives=56/100×90=50.4 of Cao
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