Math, asked by zadeajit96, 5 days ago

The amount of Rs. 1300 near Meena will be fourfold? In how many years at the rate of 10%​

Answers

Answered by pg1947945
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Question

Find the sum of money when

(ii) the final amount is Rs 11300 at 4% p.a. for 3 years 3 months.

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Solution

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Amount (A) = Rs 11300

Rate (R) = 4% p.a.

Time (T) = 3 years 3 months

= 3123 years

= 341years

= 13 / 4 years

Let the principal be Rs x

Hence,

S.I. = (P × R × T) / 100

= Rs (x × 4 × 13) / (100 × 4)

We get,

= Rs 13x / 100

Then,

Amount = Principal + Simple Interest

= Rs x + Rs 13x / 100

= Rs (x + 13x) / 100

We get,

= Rs (100x + 13x) / 100

= Rs (113x / 100)

But, the amount given is Rs 11300

Hence,

113x / 100 = 11300

x = 11300 × 100 / 113

x = 100 × 100

We get,

x = 10000

Therefore, principal (P) = Rs 10000

Answered by pm9148805
0

Principal amount = 1000

Principal amount = 1000Rate of interest = 10%

Principal amount = 1000Rate of interest = 10%Amount = 1300

Principal amount = 1000Rate of interest = 10%Amount = 1300Time = T

Principal amount = 1000Rate of interest = 10%Amount = 1300Time = TSimple interest = amount - principal amount

Principal amount = 1000Rate of interest = 10%Amount = 1300Time = TSimple interest = amount - principal amountSimple interest = 1300 - 1000

Principal amount = 1000Rate of interest = 10%Amount = 1300Time = TSimple interest = amount - principal amountSimple interest = 1300 - 1000Simple interest = 300 rupees

Principal amount = 1000Rate of interest = 10%Amount = 1300Time = TSimple interest = amount - principal amountSimple interest = 1300 - 1000Simple interest = 300 rupeesSimple interest - Principal amount × Rate of = interest x Time / 100

Principal amount = 1000Rate of interest = 10%Amount = 1300Time = TSimple interest = amount - principal amountSimple interest = 1300 - 1000Simple interest = 300 rupeesSimple interest - Principal amount × Rate of = interest x Time / 100300 1000 × 10 × T / 100

Principal amount = 1000Rate of interest = 10%Amount = 1300Time = TSimple interest = amount - principal amountSimple interest = 1300 - 1000Simple interest = 300 rupeesSimple interest - Principal amount × Rate of = interest x Time / 100300 1000 × 10 × T / 100300 = 100T

Principal amount = 1000Rate of interest = 10%Amount = 1300Time = TSimple interest = amount - principal amountSimple interest = 1300 - 1000Simple interest = 300 rupeesSimple interest - Principal amount × Rate of = interest x Time / 100300 1000 × 10 × T / 100300 = 100TT = 300/100

Principal amount = 1000Rate of interest = 10%Amount = 1300Time = TSimple interest = amount - principal amountSimple interest = 1300 - 1000Simple interest = 300 rupeesSimple interest - Principal amount × Rate of = interest x Time / 100300 1000 × 10 × T / 100300 = 100TT = 300/100T = 3 years

1000 will amount to 1300 in 3 per annum

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